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Mt. Everest is more than 8000 m tall. How fast would a rock dropped from this height be falling?

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Mt. Everest is more than 8000 m tall. How fast would a rock dropped from this height be falling when it reached sea level if there were no air resistance?

I found t=40 by plugging it into dy=1/2*g*t^2, but I don't know what to do with this information.
asked Aug 19, 2013 in Culture by pance (50,970 points)

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If t=40 then you know the rock will be accelerating at a rate of 9.8 m/s/s for those 40 seconds.
Velocity = acceleration x time
V = 9.8 m/s/s x 40 sec = 392 m/s.

(This is not at all "real world": The effects of air friction would eventually become equal to the force accelerating the rock, its weight... and it would stop accelerating.)
answered Aug 19, 2013 by ccee (307,900 points)
selected Aug 19, 2013 by pance
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